0=-4.9t^2+9.5t+3.2

Solution for 0=-4.9t^2+9.5t+3.2 equation:

0=-4.9t^2+9.5t+3.2

We move all terms to the left:

0-(-4.9t^2+9.5t+3.2)=0

We add all the numbers together, and all the variables

-(-4.9t^2+9.5t+3.2)=0

We get rid of parentheses

4.9t^2-9.5t-3.2=0

a = 4.9; b = -9.5; c = -3.2;
Δ = b2-4ac
Δ = -9.52-4·4.9·(-3.2)
Δ = 152.97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9.5)-\sqrt{152.97}}{2*4.9}=\frac{9.5-\sqrt{152.97}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9.5)+\sqrt{152.97}}{2*4.9}=\frac{9.5+\sqrt{152.97}}{9.8}
$